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.closest() should return a unique set of elements, not duplicates of the same ancestor. Fixes #6700

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adam j. sontag 2010-06-21 13:50:02 -04:00
parent 6a0942c9d5
commit a2bd8a53f3
2 changed files with 14 additions and 6 deletions
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14
src/traversing.js
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@ -53,9 +53,10 @@ jQuery.fn.extend({
},
closest: function( selectors, context ) {
var ret;
if ( jQuery.isArray( selectors ) ) {
var ret = [], cur = this[0], match, matches = {}, selector, level = 1;
var cur = this[0], match, matches = {}, selector, level = 1;
ret = [];
if ( cur && selectors.length ) {
for ( var i = 0, l = selectors.length; i < l; i++ ) {
selector = selectors[i];
@ -80,13 +81,12 @@ jQuery.fn.extend({
}
}
return ret;
return ret.length > 1 ? jQuery.unique(ret) : ret;
}
var pos = jQuery.expr.match.POS.test( selectors ) ?
jQuery( selectors, context || this.context ) : null;
return this.map(function( i, cur ) {
ret = jQuery.map(this.get(),function( cur,i ) {
while ( cur && cur.ownerDocument && cur !== context ) {
if ( pos ? pos.index(cur) > -1 : jQuery(cur).is(selectors) ) {
return cur;
@ -95,6 +95,10 @@ jQuery.fn.extend({
}
return null;
});
ret = ret.length > 1 ? jQuery.unique(ret) : ret;
return this.pushStack( ret, "closest", selectors );
},
// Determine the position of an element within