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Applied arrix's fix for getting style values on elements that aren't in the DOM, in Safari. (Bug #1482)

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John Resig 2007-08-19 07:06:15 +00:00
parent f64eb21fad
commit 735e2e8197
1 changed files with 1 additions and 1 deletions
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2
src/jquery/jquery.js vendored
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@ -1509,7 +1509,7 @@ jQuery.extend({
// then some display: none elements are involved
else {
// Locate all of the parent display: none elements
for ( var a = elem; color(a); a = a.parentNode )
for ( var a = elem; a && color(a); a = a.parentNode )
stack.unshift(a);
// Go through and make them visible, but in reverse